Uploaded file output as image in article

I'm posting a new question on this as the other one is long and I have printed it out, but it relates to image field which does not have the upload ability as yet.

As I need my users to upload the file, I would of necessity have to work with uploads field. I need, however, for this to display as an image in the article, with preset sizes.

I have copied the output file as follows with my reasoning on each aspect, and I would appreciate it if you could advise whether I'm correct or not.

    **<tr class="cat-list-row<?php echo $k = 1 - $k; ?>">

        <td width="1%"><?php echo $i+1;?></td>

        <td>**

As I do not need a list of files I assume I can delete the above lines?

            <a 

            <?php 

            $class = '';

            **if($this->params->get('params.show_in_browser', 0))

**

I'm assuming that the above is actually where it begins the output instruction, and below offers the various options?

{

                switch ($this->params->get('params.show_target', 0))

                {

                    case 0:

                        echo ' target="_blank" ';

                        echo ' href="'.$file->url.'"';

                        break;



                    case 1:

                        echo ' onclick="popUpFile'.$this->id.'(\''.$file->url.'\');return false;" ';

                        echo ' href="javascript:void(0);"';

                        break;



                    case 2:

                        echo ' href="'.$file->url.'"';

                        $class = ' class="modal"';

                        break;



                    case 3:

                        echo ' href="'.$file->url.'"';

                        break;

                }

            }

            else

            {

                echo ' target="_blank" ';

                echo ' href="'.$file->url.'"';

            }

            ?>  

            >

As the above options relate to showing the file once the link is clicked in the list, am I correct in saying that I do not need these?

My thought is that I should be rewriting echo ' href="'.$file->url.'"';

with whatever is needed to "convert" the attachment into an article image??

I have once again Googled extensively and cannot find the php needed to output an attachment (upload) file as an image and so once again I need a little assistance when you have a moment.

Again, as I do not need title, description, hits, etc, I suppose I could just delete the rest?

            <?php echo ($this->params->get('params.allow_edit_title', 0) && $file->title ? $file->title : $file->realname);?>

            </a>

            <?php if($this->descr && $file->description):?>

                <p><?php echo $file->description;?></p>

            <?php endif;?>

        </td>



        <?php if($this->hits):?>

            <td width="1%"><?php echo (int)$file->hits?></td>

        <?php endif;?>



        <?php if($this->size):?>

            <td width="1%" nowrap="nowrap"><?php echo HTMLFormatHelper::formatSize($file->size);?></td>

        <?php endif;?>