Questions about Cobalt :-)

1. Status is connceted to record not to user. It means that if you have status to completed from ome user, it will change status of the article for all users. Just like on this forum. I select status solved and it is solved for all users.

But status still may be good if you create another type let's say homework. And allow user to submit sort of comment but it is homework. Then when you change status of that homework, next lesson may be opened through status changed SQL query feature.

2. In custom template, when you list articles, just after foreach($this->items AS $item) you have to insert something like this.

if(!$item->fields_by_id[12]->access) continue;

Where 12 is an ID of the field.

3. This parameter is only for admins. Registered users do not see it. You configure default values in comment parameters.

4. FOr that, better use Cobalt type as comment adapter. Then it is simply another section of cobalt and all its parameters applys. You can restrict to only see author own records. To do so, pay attention on Type submission parameteres and Section Who can see restricted articles aparameter.

Sergey But status still may be good if you create another type let's say homework. And allow user to submit sort of comment but it is homework. Then when you change status of that homework, next lesson may be opened through status changed SQL query feature.

Is there any other way than using the status field? What do you recommend? I don't insist on using the status field.

3. This parameter is only for admins. Registered users do not see it. You configure default values in comment parameters.

I understand this, but is there a way to create a listbox (or radio bottuns) with two groups where the user sets the groups that can see the comments? For example on your template, there is a private check box at the bottom. I can have two radio buttons like "I can see", "everybody of this group can see"

Status field is good. If something like homework submission is ok for you, then status is the way to go.

Unfortunately core comments are not designed for high level accesss management. I recommend simply use cobalt type as comment adapter, then you can do almost anything and use status field for that type.

Hi Sergey,

I really feel stuck at this point. I have limited time to launch my new section, I know that Cobalt can help me to build what I need, but I nearly have no idea about how to manage what you have indicated above. I understand that you have very limited time nowadays. Can you please refer me someone with whom I can build the new section.

Hi Sergey,

I am tryng to proceed step by step before I can find a person who cen help me. So here is the question:

On the blog page, where the record titles are listed (tasks in my case), how can I display a field value (status in this case) next to the commented record title entered by current logged in user in a comment (using cobalt type as comments).

I hope you understand since I have explained you what I am trying to do before.

Try to read this

http://docs.mintjoomla.com/en/cobalt/custom-templates-general

1. In custom template, when you list articles, just after foreach($this->items AS $item) you have to insert something like this.

   if(!$item->fields_by_id[12]->access) continue;

Where 12 is an ID of the field.

ID of which field? I hve tried the id of each field one by one but the template kept giving me these errors:

Notice: Undefined offset: 10 in .../components/com_cobalt/views/records/tmpl/default_list_yenibirben.php on line 84

Notice: Trying to get property of non-object in .../components/com_cobalt/views/records/tmpl/default_list_yenibirben.php on line 84

Try make var_dump($item->fields_by_id); and you will see what in this array is keeping.

Hi Konstatin, when I did what you said, I saw that the field id was 5. When I used 5 as field id, it started to work. But, I still get the same error when I login as admin. test users don't get the error.

it's strange it's don't work for all records or not. Maybe for admin shows more records and this records haven't value for field with id = 5, so you must first3check existing

if(isset($item->fields_by_id[5])){
    echo $item->fields_by_id[5]->result;
}